JEE MAIN - Chemistry (2023 - 29th January Morning Shift - No. 10)
Chiral complex from the following is :
Here en = ethylene diamine
$$\mathrm{cis-[PtCl_2(en)_2]^{2+}}$$
$$\mathrm{trans-[Co(NH_3)_4Cl_2]^{+}}$$
$$\mathrm{trans-[PtCl_2(en)_2]^{2+}}$$
$$\mathrm{cis-[PtCl_2(NH_3)_2]}$$
Explanation
_29th_January_Morning_Shift_en_10_1.png)
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