JEE MAIN - Chemistry (2023 - 29th January Evening Shift - No. 9)
Reaction of propanamide with $$\mathrm{Br_2/KOH(aq)}$$ produces :
Propanenitrile
Propylamine
Ethylnitrile
Ethylamine
Explanation
Propanamide $$\mathrm{\buildrel {B{r_2}/KOH} \over
\longrightarrow}$$ Ethylamine
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