JEE MAIN - Chemistry (2023 - 29th January Evening Shift - No. 6)
When a hydrocarbon A undergoes combustion in the presence of air, it requires 9.5 equivalents of oxygen and produces 3 equivalents of water. What is the molecular formula of A?
$$\mathrm{C_9H_6}$$
$$\mathrm{C_6H_6}$$
$$\mathrm{C_8H_6}$$
$$\mathrm{C_9H_9}$$
Explanation
$${C_x}{H_y} + \left( {x + {y \over 4}} \right){O_2} \to xC{O_2} + {y \over 2}{H_2}O$$
$${y \over 2} = 3$$
$$y = 6$$
$$x + {y \over 4} = {{19} \over 2}$$
$$x = {{19} \over 2} - {3 \over 2} = 8$$
So, formula is $${C_8}{H_6}$$.
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