JEE MAIN - Chemistry (2023 - 29th January Evening Shift - No. 20)
When 0.01 mol of an organic compound containing 60% carbon was burnt completely, 4.4 g of CO$$_2$$ was produced. The molar mass of compound is _____________ g mol$$^{-1}$$ (Nearest integer).
Answer
200
Explanation
Number of moles of $$C{O_2} = {{4.4} \over {44}} = 0.1$$
$$\therefore$$ Number of moles of C in 1 mole of compound = 10
$$\therefore$$ $$120 = {{60} \over {100}} \times (x)$$ [where x is molar mass of OC]
Molar mass = 200 g mol$$^{-1}$$
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