JEE MAIN - Chemistry (2023 - 25th January Morning Shift - No. 8)
'25 volume' hydrogen peroxide means
1 L marketed solution contains 75 g of H$$_2$$O$$_2$$.
1 L marketed solution contains 250 g of H$$_2$$O$$_2$$.
1 L marketed solution contains 25 g of H$$_2$$O$$_2$$.
100 mL marketed solution contains 25 g of H$$_2$$O$$_2$$.
Explanation
Molarity of $\mathrm{H}_{2} \mathrm{O}_{2}$ soln $=\frac{\text { volume strength }}{11.2}$
$=\frac{25}{11.2}=2.23 \mathrm{M}$
$\therefore$ amount of $\mathrm{H}_{2} \mathrm{O}_{2}$ in one litre $=2.23 \times 34=75 \mathrm{gm}$
$=\frac{25}{11.2}=2.23 \mathrm{M}$
$\therefore$ amount of $\mathrm{H}_{2} \mathrm{O}_{2}$ in one litre $=2.23 \times 34=75 \mathrm{gm}$
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