JEE MAIN - Chemistry (2023 - 25th January Evening Shift - No. 11)
A chloride salt solution acidified with dil.HNO$$_3$$ gives a curdy white precipitate, [A], on addition of AgNO$$_3$$. [A] on treatment with NH$$_4$$OH gives a clear solution B. A and B are respectively :
$$\mathrm{H[AgCl_3]~\&~(NH_4)[Ag(OH)_2]}$$
$$\mathrm{AgCl~\&~[Ag(NH_3)_2]Cl}$$
$$\mathrm{H[AgCl_3]~\&~[Ag(NH_3)_2]Cl}$$
$$\mathrm{AgCl~\&~(NH_4)[Ag(OH)_2]}$$
Explanation
$\mathrm{Cl}^{-}(\mathrm{aq})+\mathrm{AgNO}_{3}(\mathrm{aq}) \stackrel{\text { dil } \mathrm{HNO}_{3}}{\longrightarrow} \underset{(\mathrm{A})}{\mathrm{AgCl}} \downarrow$
$$ \mathrm{AgCl} \downarrow+2 \mathrm{NH}_4 \mathrm{OH}(\mathrm{aq}) \rightarrow\underset{(B)}{\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right]} \mathrm{Cl}(\mathrm{aq})+2 \mathrm{H}_2 \mathrm{O} $$
$\therefore(\mathrm{A})$ is $\mathrm{AgCl}$ and $(\mathrm{B})$ is $\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right] \mathrm{Cl}$
$$ \mathrm{AgCl} \downarrow+2 \mathrm{NH}_4 \mathrm{OH}(\mathrm{aq}) \rightarrow\underset{(B)}{\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right]} \mathrm{Cl}(\mathrm{aq})+2 \mathrm{H}_2 \mathrm{O} $$
$\therefore(\mathrm{A})$ is $\mathrm{AgCl}$ and $(\mathrm{B})$ is $\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right] \mathrm{Cl}$
Comments (0)
