JEE MAIN - Chemistry (2023 - 24th January Morning Shift - No. 22)
The d-electronic configuration of $$\mathrm{[CoCl_4]^{2-}}$$ in tetrahedral crystal field in $${e^mt_2^n}$$. Sum of "m" and "number of unpaired electrons" is ___________
Answer
7
Explanation
$$
\mathrm{Co}^{2+}: 3 \mathrm{~d}^7 4 \mathrm{~s}^0, \mathrm{Cl}^{-}: \mathrm{WFL}
$$
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Configuration $\mathrm{e}^4 \mathrm{t}_2{ }^3: \mathrm{m}=4$
Number of unpaired electrons $=3$
So, answer $=7$
Configuration $\mathrm{e}^4 \mathrm{t}_2{ }^3: \mathrm{m}=4$
Number of unpaired electrons $=3$
So, answer $=7$
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