JEE MAIN - Chemistry (2023 - 24th January Morning Shift - No. 11)
Order of Covalent bond;
$$\mathrm{A.~KF > KI ; LiF > KF}$$
$$\mathrm{B.~KF < KI ; LiF > KF}$$
$$\mathrm{C.~SnCl_4 > SnCl_2 ; CuCl > NaCl}$$
$$\mathrm{D.~LiF > KF ; CuCl < NaCl}$$
$$\mathrm{E.~KF < KI ; CuCl > NaCl}$$
Choose the correct answer from the options given below :
B, C only
A, B only
C, E only
B, C, E only
Explanation
B is correct $\mathrm{KF}<\mathrm{KI}$; $\mathrm{LiF}>\mathrm{KF}$
$\mathrm{C}$ is correct $\underset{+4}{\mathrm{SnCl}_{4}}>\underset{+2}{\mathrm{SnCl}_{2}} ; \mathrm{CuCl}>\mathrm{NaCl}$
$\mathrm{E}$ is correct $\mathrm{KF}<\mathrm{KI}$; $\mathrm{CuCl}>\mathrm{NaCl}$
$\mathrm{C}$ is correct $\underset{+4}{\mathrm{SnCl}_{4}}>\underset{+2}{\mathrm{SnCl}_{2}} ; \mathrm{CuCl}>\mathrm{NaCl}$
$\mathrm{E}$ is correct $\mathrm{KF}<\mathrm{KI}$; $\mathrm{CuCl}>\mathrm{NaCl}$
Comments (0)
