JEE MAIN - Chemistry (2023 - 24th January Evening Shift - No. 5)
Choose the correct representation of conductometric titration of benzoic acid vs sodium hydroxide.
_24th_January_Evening_Shift_en_5_1.png)
_24th_January_Evening_Shift_en_5_2.png)
_24th_January_Evening_Shift_en_5_3.png)
_24th_January_Evening_Shift_en_5_4.png)
Explanation
$\underset{\text { (wA) }}{\mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}}+\underset{\text { (SB) }}{\mathrm{NaOH}} \longrightarrow \underset{\text { (Salt) }}{\mathrm{C}_6 \mathrm{H}_5 \mathrm{COONa}}+\mathrm{H}_2 \mathrm{O}$
_24th_January_Evening_Shift_en_5_5.png)
(A) $\rightarrow$ (B) Free $\mathrm{H}^{+}$ions are replaced by $\mathrm{Na}^{\oplus}$ which decreases conductance.
(B) $\rightarrow$ (C) Un-dissociated benzoic acid reacts with $\mathrm{NaOH}$ and forms salt which increases ions & conductance increases.
(C) $\rightarrow$ (D) After equivalence point at (3), $\mathrm{NaOH}$ added further increases $\mathrm{Na}^{\oplus} \& \mathrm{OH}^{\odot}$ ions which further increases the conductance.
(A) $\rightarrow$ (B) Free $\mathrm{H}^{+}$ions are replaced by $\mathrm{Na}^{\oplus}$ which decreases conductance.
(B) $\rightarrow$ (C) Un-dissociated benzoic acid reacts with $\mathrm{NaOH}$ and forms salt which increases ions & conductance increases.
(C) $\rightarrow$ (D) After equivalence point at (3), $\mathrm{NaOH}$ added further increases $\mathrm{Na}^{\oplus} \& \mathrm{OH}^{\odot}$ ions which further increases the conductance.
Comments (0)
