JEE MAIN - Chemistry (2023 - 24th January Evening Shift - No. 1)
The number of s-electrons present in an ion with 55 protons in its unipositive state is
10
9
12
8
Explanation
The number of protons in an element determines its atomic number, which is the number of electrons in a neutral atom of the element. The unipositive state of an ion indicates that it has lost one electron. Therefore, the number of electrons in a unipositive ion is one less than the atomic number.
The element with 55 protons is cesium (Cs), which is in group 1 of the periodic table. Group 1 elements have one valence electron in the s sublevel of their outermost energy level.
In a neutral atom of cesium, there are 55 electrons, with the electron configuration [Xe] 6s1. When cesium loses one electron to form a unipositive ion (Cs+), the resulting ion has 54 electrons.
Out of this 54 electrons s subshell has 10 electrons in 1s2, 2s2, 3s2, 4s2, 5s2.
The element with 55 protons is cesium (Cs), which is in group 1 of the periodic table. Group 1 elements have one valence electron in the s sublevel of their outermost energy level.
In a neutral atom of cesium, there are 55 electrons, with the electron configuration [Xe] 6s1. When cesium loses one electron to form a unipositive ion (Cs+), the resulting ion has 54 electrons.
Out of this 54 electrons s subshell has 10 electrons in 1s2, 2s2, 3s2, 4s2, 5s2.
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