JEE MAIN - Chemistry (2023 - 1st February Morning Shift - No. 9)
A solution of $$\mathrm{FeCl_3}$$ when treated with $$\mathrm{K_4[Fe(CN)_6]}$$ gives a prussium blue precipitate due to the formation of :
$$\mathrm{Fe[Fe(CN)_{6}]}$$
$$\mathrm{Fe_{4}[Fe(CN)_{6}]_{3}}$$
$$\mathrm{Fe_{3}[Fe(CN)_{6}]_{2}}$$
$$\mathrm{K[Fe_{2}(CN)_{6}]}$$
Explanation
$\mathrm{Fe}^{3+}+\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-} \longrightarrow \mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}$(Prussium Blue)
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