JEE MAIN - Chemistry (2023 - 1st February Morning Shift - No. 5)
But-2-yne is reacted separately with one mole of Hydrogen as shown below :
_1st_February_Morning_Shift_en_5_1.png)
A. A is more soluble than B.
B. The boiling point & melting point of A are higher and lower than B respectively.
C. A is more polar than B because dipole moment of A is zero.
D. $$\mathrm{Br_2}$$ adds easily to B than A.
Identify the incorrect statements from the options given below :
A and B only
A, C & D only
B, C & D only
C and D only
Explanation
_1st_February_Morning_Shift_en_5_2.png)
cis-2-butene is more polar that is why it's solubility is more than trans-2-butene.
$$ \therefore $$ A is correct.
cis-2-butene has a lower melting point than trans-2-butene as trans-form has compact packing crystal lattice. cis-2-butene is polar so, it has higher boiling point than trans-form.
$$ \therefore $$ B is also correct.
cis-2-butene is more polar but dipole moment of cis-2-butene(A) is not zero.
$$ \therefore $$ C is incorrect.
'Cis' structure is less stable than 'Trans" structure. Less stable means more reactive. So Cis - But-2-ene(A) will react more easily with Br2.
$$ \therefore $$ D is also incorrect.
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