JEE MAIN - Chemistry (2023 - 1st February Evening Shift - No. 9)
The effect of addition of helium gas to the following reaction in equilibrium state, is :
$$\mathrm{PCl}_{5}(\mathrm{g}) \rightleftharpoons \mathrm{PCl}_{3}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{g})$$
the equilibrium will shift in the forward direction and more of $$\mathrm{Cl}_{2}$$ and $$\mathrm{PCl}_{3}$$ gases will be produced.
addition of helium will not affect the equilibrium.
helium will deactivate $$\mathrm{PCl}_{5}$$ and reaction will stop.
the equilibrium will go backward due to suppression of dissociation of $$\mathrm{PCl}_{5}$$.
Explanation
$$
\mathrm{PCI}_5(\mathrm{~g}) \rightleftharpoons \mathrm{PCl}_3(\mathrm{~g})+\mathrm{Cl}_2(\mathrm{~g})
$$
Case 1 : At constant pressure, the addition of inert gas (helium) will shift the reaction where number of moles of gaseous substances are more hence, the reaction will proceed in forward direction. Then answer will be $A$.
Case 2 : At constant volume, addition of He will not affect the equilibrium so reaction will not shift in any direction then answer will be $B$.
Case 1 : At constant pressure, the addition of inert gas (helium) will shift the reaction where number of moles of gaseous substances are more hence, the reaction will proceed in forward direction. Then answer will be $A$.
Case 2 : At constant volume, addition of He will not affect the equilibrium so reaction will not shift in any direction then answer will be $B$.
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