JEE MAIN - Chemistry (2023 - 1st February Evening Shift - No. 4)

In a reaction,

JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 75 English

reagents 'X' and 'Y' respectively are :

$$\mathrm{CH}_{3} \mathrm{OH} / \mathrm{H}^{+}, \Delta$$ and $$\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O} / \mathrm{H}^{+}$$
$$\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O} / \mathrm{H}^{+}$$ and $$\mathrm{CH}_{3} \mathrm{OH} / \mathrm{H}^{+}, \Delta$$
$$\mathrm{CH}_{3} \mathrm{OH} / \mathrm{H}^{+}, \Delta$$ and $$\mathrm{CH}_{3} \mathrm{OH} / \mathrm{H}^{+}, \Delta$$
$$\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O} / \mathrm{H}^{+}$$ and $$\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O} / \mathrm{H}^{+}$$

Explanation

JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 75 English Explanation

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