JEE MAIN - Chemistry (2023 - 1st February Evening Shift - No. 23)
$$\mathrm{A}$$ $$\rightarrow \mathrm{B}$$
The above reaction is of zero order. Half life of this reaction is $$50 \mathrm{~min}$$. The time taken for the concentration of $$\mathrm{A}$$ to reduce to one-fourth of its initial value is ____________ min. (Nearest integer)
Answer
75
Explanation
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$ \mathrm{a}-\mathrm{x}=\frac{\mathrm{a}}{4} \Rightarrow \mathrm{x}=\frac{3 \mathrm{a}}{4} $
$ \mathrm{t}_{1 / 2}=\frac{\mathrm{a}}{2 \mathrm{~K}}=50 \mathrm{~min} .$
$ \Rightarrow \frac{\mathrm{a}}{\mathrm{K}}=100 \mathrm{~min} . $
$ \mathrm{t}=\frac{\mathrm{x}}{\mathrm{K}}=\frac{3 \mathrm{a}}{4 \mathrm{~K}}=75 \mathrm{~min} $
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