JEE MAIN - Chemistry (2023 - 15th April Morning Shift - No. 11)
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In the above conversion the correct sequence of reagents to be added is
(i) $\mathrm{KMnO}_{4}$, (ii) $\mathrm{Br}_{2} / \mathrm{Fe}$, (iii) $\mathrm{Fe} / \mathrm{H}^{+}$, (iv) $\mathrm{Cl}_{2}$
(i) $\mathrm{Fe} / \mathrm{H}^{+}$, (ii) $\mathrm{HONO}$, (iii) $\mathrm{CuCl}$, (iv) $\mathrm{KMnO}_4$, (v) $\mathrm{Br}_2$
(i) $\mathrm{Br}_{2} / \mathrm{Fe}$, (ii) $\mathrm{Fe} / \mathrm{H}^{+}$, (iii) $\mathrm{HONO}$, (iv) $\mathrm{CuCl}$, (v) $\mathrm{KMnO}_{4}$
(i) $\mathrm{Br}_{2} / \mathrm{Fe}$, (ii) $\mathrm{Fe} / \mathrm{H}^{+}$, (iii) $\mathrm{KMnO}_{4}$, (iv) $\mathrm{Cl}_{2}$
Explanation
_15th_April_Morning_Shift_en_11_2.png)
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