JEE MAIN - Chemistry (2023 - 13th April Morning Shift - No. 3)
In the following reaction 'X' is
$$\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{4} \mathrm{CH}_{2} \mathrm{Cl}$$
_13th_April_Morning_Shift_en_3_2.png)
$$\mathrm{Cl}-\mathrm{CH}_{2}-\left(\mathrm{CH}_{2}\right)_{4}-\mathrm{CH}_{2}-\mathrm{Cl}$$
_13th_April_Morning_Shift_en_3_3.png)
Explanation
$\mathrm{n}$-alkanes on heating in this presence of anhydrous $\mathrm{AlCl}_3$ and hydrogen chloride gas isomerise to branched chain alkanes. The major product has one methyl side chain.
_13th_April_Morning_Shift_en_3_4.png)
_13th_April_Morning_Shift_en_3_4.png)
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