JEE MAIN - Chemistry (2023 - 12th April Morning Shift - No. 19)

The mass of NH$$_3$$ produced when 131.8 kg of cyclohexanecarbaldehyde undergoes Tollen's test is ________ kg. (Nearest Integer)

Molar Mass of

C = 12g/mol

N = 14g/mol

O = 16g/mol

Answer
60

Explanation

$$ \begin{aligned} & \mathrm{RCHO}+2\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right] \mathrm{OH} \rightarrow \mathrm{RCOONH}_4+2 \mathrm{Ag} +3 \mathrm{NH}_3+\mathrm{H}_2 \mathrm{O} \\\\ & \text {moles }=\frac{131.8 \times 10^3}{112}=1.176 \times 10^3 \\\\ & 1 \text { mole of aldehyde produces } 3 \text { moles of } \mathrm{NH}_3 \\\\ & 1.176 \times 10^3 \mathrm{~mol} \text { aldehyde will produce } \\\\ & =3 \times 1.176 \times 10^3 \text { moles of } \mathrm{NH}_3 \\\\ & \text {Mass of } \mathrm{NH}_3 \text { produced }=3 \times 1.176 \times 10^3 \times 17 \\\\ & =59.97 \times 10^3 \mathrm{~g} \\\\ & \approx 60~ \mathrm{kg} \end{aligned} $$

Comments (0)

Advertisement