JEE MAIN - Chemistry (2023 - 12th April Morning Shift - No. 19)
The mass of NH$$_3$$ produced when 131.8 kg of cyclohexanecarbaldehyde undergoes Tollen's test is ________ kg. (Nearest Integer)
Molar Mass of
C = 12g/mol
N = 14g/mol
O = 16g/mol
Answer
60
Explanation
$$
\begin{aligned}
& \mathrm{RCHO}+2\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right] \mathrm{OH} \rightarrow \mathrm{RCOONH}_4+2 \mathrm{Ag} +3 \mathrm{NH}_3+\mathrm{H}_2 \mathrm{O} \\\\
& \text {moles }=\frac{131.8 \times 10^3}{112}=1.176 \times 10^3 \\\\
& 1 \text { mole of aldehyde produces } 3 \text { moles of } \mathrm{NH}_3 \\\\
& 1.176 \times 10^3 \mathrm{~mol} \text { aldehyde will produce } \\\\
& =3 \times 1.176 \times 10^3 \text { moles of } \mathrm{NH}_3 \\\\
& \text {Mass of } \mathrm{NH}_3 \text { produced }=3 \times 1.176 \times 10^3 \times 17 \\\\
& =59.97 \times 10^3 \mathrm{~g} \\\\
& \approx 60~ \mathrm{kg}
\end{aligned}
$$
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