JEE MAIN - Chemistry (2023 - 12th April Morning Shift - No. 17)
Three organic compounds A, B and $$\mathrm{C}$$ were allowed to run in thin layer chromatography using hexane and gave the following result (see figure). The $$\mathrm{R}_{\mathrm{f}}$$ value of the most polar compound is ____________ $$\times 10^{-2}$$
_12th_April_Morning_Shift_en_17_1.png)
Answer
25
Explanation
In thin layer chromatography using hexane, the least polar compound will rise to maximum height and most polar compound will rise to minimum height.
$\therefore \mathrm{R}_{\mathrm{f}}$ value for most polar compound
$$ \begin{aligned} & =\frac{2}{8}=0.25 \\\\ & =25 \times 10^{-2} \end{aligned} $$
$\therefore \mathrm{R}_{\mathrm{f}}$ value for most polar compound
$$ \begin{aligned} & =\frac{2}{8}=0.25 \\\\ & =25 \times 10^{-2} \end{aligned} $$
Comments (0)
