JEE MAIN - Chemistry (2023 - 11th April Morning Shift - No. 5)
Match List - I with List - II:
List - I Species | List - II Geometry/Shape | ||
---|---|---|---|
A. | $$\mathrm{H_3O^+}$$ | I. | Tetrahedral |
B. | Acetylide anion | II. | Linear |
C. | $$\mathrm{NH_4^+}$$ | III. | Pyramidal |
D. | $$\mathrm{ClO_2^-}$$ | IV. | Bent |
Choose the correct answer from the options given below:
Explanation
Let's consider each species in List I and determine their geometries/shapes.
A. $\mathrm{H_3O^+}$: This ion is formed by the addition of a proton to a water molecule. The central atom (O) is surrounded by three Hydrogen atoms and one lone pair, making its shape pyramidal.
B. Acetylide anion: The acetylide ion ($\mathrm{C_2H^-}$ or $\mathrm{C_2^{2-}}$) has a linear geometry as the three atoms are in a straight line.
C. $\mathrm{NH_4^+}$: The ammonium ion has a central nitrogen atom surrounded by four hydrogen atoms, giving it a tetrahedral geometry.
D. $\mathrm{ClO_2^-}$: The chlorite ion has a central chlorine atom surrounded by two oxygen atoms and one lone pair, which gives it a bent or V-shaped geometry.
Matching these to List II, we get:
A. $\mathrm{H_3O^+}$ - III. Pyramidal
B. Acetylide anion - II. Linear
C. $\mathrm{NH_4^+}$ - I. Tetrahedral
D. $\mathrm{ClO_2^-}$ - IV. Bent
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