JEE MAIN - Chemistry (2023 - 11th April Morning Shift - No. 16)
A solution of sugar is obtained by mixing $$200 \mathrm{~g}$$ of its $$25 \%$$ solution and $$500 \mathrm{~g}$$ of its $$40 \%$$ solution (both by mass). The mass percentage of the resulting sugar solution is ___________ (Nearest integer)
Answer
36
Explanation
Let's first calculate the amount of sugar in each of the solutions :
In the 25% sugar solution, the amount of sugar is 25% of 200 g, which equals 50 g.
In the 40% sugar solution, the amount of sugar is 40% of 500 g, which equals 200 g.
Now, let's mix these two solutions together:
The total amount of sugar in the combined solution is 50 g (from the 25% solution) + 200 g (from the 40% solution) = 250 g.
The total weight of the combined solution is 200 g (of the 25% solution) + 500 g (of the 40% solution) = 700 g.
Therefore, the mass percentage of sugar in the combined solution is $$ =\frac{250}{700} \times 100 $$ = 35.71%
Rounding to the nearest integer gives 36%. So, the mass percentage of the resulting sugar solution is 36%.
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