JEE MAIN - Chemistry (2023 - 11th April Evening Shift - No. 7)
Match List I with List II
| LIST I Complex |
LIST II Colour |
||
|---|---|---|---|
| A. | $$Mg(N{H_4})P{O_4}$$ | I. | brown |
| B. | $${K_3}[Co{(N{O_2})_6}]$$ | II. | white |
| C. | $$MnO{(OH)_2}$$ | III. | yellow |
| D. | $$F{e_4}{[Fe{(CN)_6}]_3}$$ | IV. | blue |
Choose the correct answer from the options given below :
A-II, B-IV, C-I, D-III
A-II, B-III, C-I, D-IV
A-III, B-IV, C-II, D-I
A-II, B-III, C-IV, D-I
Explanation
In this problem, we are matching chemical compounds with their corresponding color. Let's go over each one :
A. $$Mg(NH_4)PO_4$$ - Magnesium ammonium phosphate is white in color, so A matches with II.
B. $$K_3[Co(NO_2)_6]$$ - Potassium hexanitritocobaltate(III) is a yellow complex, so B matches with III.
C. $$MnO(OH)_2$$ - Manganese hydroxide is brown in color, so C matches with I.
D. $$Fe_4[Fe(CN)_6]_3$$ - Prussian blue or Ferric ferrocyanide is deep blue in color, so D matches with IV.
So, the correct option is Option B: A-II, B-III, C-I, D-IV.
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