JEE MAIN - Chemistry (2023 - 11th April Evening Shift - No. 13)
For a chemical reaction $$\mathrm{A}+\mathrm{B} \rightarrow$$ Product, the order is 1 with respect to $$\mathrm{A}$$ and $$\mathrm{B}$$.
| $$\mathrm{Rate}$$ $$\mathrm{mol~L^{-1}~S^{-1}}$$ |
$$\mathrm{[A]}$$ $$\mathrm{mol~L^{-1}}$$ |
$$\mathrm{[B]}$$ $$\mathrm{mol~L^{-1}}$$ |
|---|---|---|
| 0.10 | 20 | 0.5 |
| 0.40 | $$x$$ | 0.5 |
| 0.80 | 40 | $$y$$ |
What is the value of $$x$$ and $$y$$ ?
80 and 4
160 and 4
80 and 2
40 and 4
Explanation
$$
\begin{aligned}
& \mathrm{r}=\mathrm{K}[\mathrm{A}]^1[\mathrm{~B}]^1 \\\\
& 0.1=\mathrm{K}(20)^1(0.5)^1 ........(i) \\\\
& 0.40=\mathrm{K}(\mathrm{x})^1(0.5)^1 ........(ii) \\\\
& 0.80=\mathrm{K}(40)^1(\mathrm{y})^1 ........(iii)
\end{aligned}
$$
From (i) and (ii)
$$ x=80 $$
From (i) and (iii)
$$ y=2 $$
From (i) and (ii)
$$ x=80 $$
From (i) and (iii)
$$ y=2 $$
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