JEE MAIN - Chemistry (2023 - 10th April Morning Shift - No. 21)
In the following reactions, the total number of oxygen atoms in X and Y is ___________.
Na$$_2$$O + H$$_2$$O $$\to$$ 2X
Cl$$_2$$O$$_7$$ + H$$_2$$O $$\to$$ 2Y
Answer
5
Explanation
$$
\begin{aligned}
& \mathrm{Na}_2 \mathrm{O}+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{NaOH}(\mathrm{X}) \\\\
& \mathrm{Cl}_2 \mathrm{O}_7+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{HClO}_4(\mathrm{Y})
\end{aligned}
$$
$X$ has one $O$ and $Y$ has four $O$
$X$ has one $O$ and $Y$ has four $O$
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