JEE MAIN - Chemistry (2023 - 10th April Morning Shift - No. 16)

The number of bent-shaped molecule/s from the following is __________

N$$_3^-$$, NO$$_2^-$$, I$$_3^-$$, O$$_3$$, SO$$_2$$

Answer
3

Explanation

A bent-shaped molecule has a molecular geometry with a central atom bonded to two other atoms and one or two pairs of non-bonding electrons. The VSEPR (Valence Shell Electron Pair Repulsion) theory helps us predict the shapes of molecules.

Let's consider the given molecules:

  1. N$_3^-$: The azide ion has a linear shape, not bent. The nitrogen in the middle is connected to two other nitrogens and there are no lone pairs on the central atom.


  2. NO$_2^-$: The nitrite ion has a bent shape. The central nitrogen atom is connected to two oxygen atoms and has one lone pair of electrons, giving it a bent geometry.


  3. I$_3^-$: The triiodide ion has a linear shape, not bent. The central iodine atom is connected to two other iodine atoms and there are no lone pairs on the central atom.


  4. O$_3$: Ozone has a bent shape. The central oxygen atom is connected to two other oxygen atoms and has one lone pair of electrons, giving it a bent geometry.


  5. SO$_2$: Sulfur dioxide has a bent shape. The central sulfur atom is connected to two oxygen atoms and has one lone pair of electrons, giving it a bent geometry.

Therefore, there are 3 bent-shaped molecules: NO$_2^-$, O$_3$, and SO$_2$.

Comments (0)

Advertisement