JEE MAIN - Chemistry (2023 - 10th April Morning Shift - No. 15)
In potassium ferrocyanide, there are ________ pairs of electrons in the $$t_{2g}$$ set of orbitals.
Answer
3
Explanation
$\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]$
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$$ \begin{aligned} & \mathrm{Fe}^{+2}=[\mathrm{Ar}] 3 \mathrm{~d}^6 \\\\ & \mathrm{CN}^{-}=\mathrm{SFL} \end{aligned} $$
$\mathrm{t}_{2 \mathrm{~g}}$ contain 6 electron so it become 3 pairs
$$ \begin{aligned} & \mathrm{Fe}^{+2}=[\mathrm{Ar}] 3 \mathrm{~d}^6 \\\\ & \mathrm{CN}^{-}=\mathrm{SFL} \end{aligned} $$
$\mathrm{t}_{2 \mathrm{~g}}$ contain 6 electron so it become 3 pairs
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