JEE MAIN - Chemistry (2023 - 10th April Evening Shift - No. 10)
In Carius tube, an organic compound '$$\mathrm{X}$$' is treated with sodium peroxide to form a mineral acid 'Y'.
The solution of $$\mathrm{BaCl}_{2}$$ is added to '$$\mathrm{Y}$$' to form a precipitate 'Z'. 'Z' is used for the quantitative estimation of an extra element. '$$\mathrm{X}$$' could be
Cytosine
Methionine
Chloroxylenol
A nucleotide
Explanation
$\mathrm{X} \stackrel{\mathrm{Na}_2 \mathrm{O}_2}{\longrightarrow} \mathrm{Y} \stackrel{\mathrm{BaCl}_2}{\longrightarrow} \underset{\left[\mathrm{BaSO}_4\right]}{\mathrm{Z}}$
Methionine: $\mathrm{C}_5 \mathrm{H}_{11} \mathrm{NO}_2 \mathrm{S}$
_10th_April_Evening_Shift_en_10_1.png)
Methionine: $\mathrm{C}_5 \mathrm{H}_{11} \mathrm{NO}_2 \mathrm{S}$
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