JEE MAIN - Chemistry (2022 - 30th June Morning Shift - No. 2)
For a solution of the gases A, B, C and D in water at 298 K, the values of Henry's law constant (KH) are 30.40, 2.34, 1.56 $$\times$$ 10$$-$$5 and 0.513 k bar respectively. In the given graph, the lines marked as 'p' and 's' correspond respectively to :
_30th_June_Morning_Shift_en_2_1.png)
A and C
B and A
D and A
C and D
Explanation
According to Henry's law $p={K_{H}} \times x$
for $x$ constant $: p ~ \alpha ~ K_{\mathrm{i}}$
$p$ has max partial pressures.
So it should have maximum $K_{\mathrm{H}}$ and $s$ have minimum partial pressure, So $K_{H}$ should be minimum.
for $x$ constant $: p ~ \alpha ~ K_{\mathrm{i}}$
$p$ has max partial pressures.
So it should have maximum $K_{\mathrm{H}}$ and $s$ have minimum partial pressure, So $K_{H}$ should be minimum.
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