JEE MAIN - Chemistry (2022 - 30th June Morning Shift - No. 15)
Blister copper is produced by reaction of copper oxide with copper sulphide.
2Cu2O + Cu2S $$\to$$ 6Cu + SO2
When 2.86 $$\times$$ 103 g of Cu2O and 4.77 $$\times$$ 103 g of Cu2S are used for reaction, the mass of copper produced is _____________ g. (nearest integer)
(Atomic mass of Cu = 63.5 a.m. u, S = 32.0 a.m. u, O = 16.0 a.m. u)
Answer
3810
Explanation
moles of $\mathrm{Cu}_{2} \mathrm{O}=\frac{2.86 \times 10^{3}}{143}=20$
moles of $\mathrm{Cu}_{2} \mathrm{S}=\frac{4.77 \times 10^{3}}{159}=30$
$\mathrm{Cu}_{2} \mathrm{O}$ is limiting reagent
$$ \begin{array}{lccc} 2 \mathrm{Cu}_{2} \mathrm{O} & + & \mathrm{Cu}_{2} \mathrm{~S} \longrightarrow & 6 \mathrm{Cu} & + & \mathrm{SO}_{2} \\ 20 && 30 & - & & - \\ - & &20 & 60 & & 10 \end{array} $$
Mass of copper $=60 \times 63.5=3810 \mathrm{~g}$
moles of $\mathrm{Cu}_{2} \mathrm{S}=\frac{4.77 \times 10^{3}}{159}=30$
$\mathrm{Cu}_{2} \mathrm{O}$ is limiting reagent
$$ \begin{array}{lccc} 2 \mathrm{Cu}_{2} \mathrm{O} & + & \mathrm{Cu}_{2} \mathrm{~S} \longrightarrow & 6 \mathrm{Cu} & + & \mathrm{SO}_{2} \\ 20 && 30 & - & & - \\ - & &20 & 60 & & 10 \end{array} $$
Mass of copper $=60 \times 63.5=3810 \mathrm{~g}$
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