JEE MAIN - Chemistry (2022 - 29th June Morning Shift - No. 11)
17.0 g of NH3 completely vapourises at $$-$$33.42$$^\circ$$C and 1 bar pressure and the enthalpy change in the process is 23.4 kJ mol$$-$$1. The enthalpy change for the vapourisation of 85 g of NH3 under the same conditions is _________ kJ.
Answer
117
Explanation
Number of moles of $\mathrm{NH}_{3}=5$
So, required $\Delta \mathrm{H}=5 \times 23.4$
$$ =117 \mathrm{~kJ} $$
So, required $\Delta \mathrm{H}=5 \times 23.4$
$$ =117 \mathrm{~kJ} $$
Comments (0)
