JEE MAIN - Chemistry (2022 - 29th June Evening Shift - No. 9)
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The stable carbocation formed in the above reaction is
$$C{H_3}C{H_2}\mathop C\limits^ \oplus {H_2}$$
$$C{H_3}\mathop C\limits^ \oplus {H_2}$$
$$C{H_3} - \mathop C\limits^ \oplus H - C{H_3}$$
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Explanation
Initially $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}^{+}$ is formed. On rearrangement $\mathrm{CH}_{3}-\mathrm{CH}-\mathrm{CH}_{3}$ stable carbocation is formed.
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