JEE MAIN - Chemistry (2022 - 29th June Evening Shift - No. 18)
The equation
k = (6.5 $$\times$$ 1012s$$-$$1)e$$-$$26000K/T
is followed for the decomposition of compound A. The activation energy for the reaction is ________ kJ mol$$-$$1. [nearest integer]
(Given : R = 8.314 J K$$-$$1 mol$$-$$1)
Answer
216
Explanation
$k=A e^{\frac{-E_{a}}{R T}}$
$$ \begin{aligned} \frac{E_{a}}{R T} &=\frac{26000}{T} \\\\ E_{a} &=26000 \times 8.314 \\\\ &=216164 \mathrm{~J} \\\\ &=216 \mathrm{~kJ} \end{aligned} $$
$$ \begin{aligned} \frac{E_{a}}{R T} &=\frac{26000}{T} \\\\ E_{a} &=26000 \times 8.314 \\\\ &=216164 \mathrm{~J} \\\\ &=216 \mathrm{~kJ} \end{aligned} $$
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