JEE MAIN - Chemistry (2022 - 29th July Morning Shift - No. 23)
In bromination of Propyne, with Bromine, 1, 1, 2, 2-tetrabromopropane is obtained in 27% yield. The amount of 1, 1, 2, 2-tetrabromopropane obtained from 1 g of Bromine in this reaction is ___________ $$\times$$ 10$$-$$1 g. (Nearest integer)
(Molar Mass : Bromine = 80 g/mol)
Answer
3
Explanation
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2 moles $\mathrm{Br}_{2} \equiv 1$ mole 1,1,2,2-tetrabromopropane $\frac{1}{160}$ mole $\mathrm{Br}_{2}$
$\equiv \frac{1}{2} \times \frac{1}{160}$ mole 1,1,2,2-tetrabromopropane
But yield of reaction is only $27 \%$
Moles of 1,1,2,2-tetrabromopropane
$$ =\frac{1}{2} \times \frac{1}{160} \times \frac{27}{100} $$
Molar mass of 1,1,2,2-tetrabromopropane $=360 \mathrm{~g}$ Mass of 1,1,2,2-tetrabromopropane
$$ \begin{aligned} &=\frac{1}{2} \times \frac{1}{160} \times \frac{27}{100} \times 360 \mathrm{~g} \\\\ &\approx 3 \times 10^{-1} \mathrm{~g} \end{aligned} $$
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