JEE MAIN - Chemistry (2022 - 29th July Evening Shift - No. 20)
Sum of oxidation state (magnitude) and coordination number of cobalt in $$\mathrm{Na}\left[\mathrm{Co}(\mathrm{bpy}) \mathrm{Cl}_{4}\right]$$ is _________.
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Answer
9
Explanation
$\mathrm{Na}\left[\mathrm{Co}(\mathrm{bpy}) \mathrm{Cl}_{4}\right]$
Oxidation state of cobalt $=+3$
Coordination number of cobalt $=6$
[As bpy is bidentate]
So, sum $=9$
Oxidation state of cobalt $=+3$
Coordination number of cobalt $=6$
[As bpy is bidentate]
So, sum $=9$
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