JEE MAIN - Chemistry (2022 - 29th July Evening Shift - No. 12)
When ethanol is heated with conc. $$\mathrm{H}_{2} \mathrm{SO}_{4}$$, a gas is produced. The compound formed, when this gas is treated with cold dilute aqueous solution of Baeyer's reagent, is
formaldehyde
formic acid
glycol
ethanoic acid
Explanation
$$$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{OH} \frac{\text { Conc. } \mathrm{H}_{2} \mathrm{SO}_{4}}{\Delta} \mathrm{CH}_{2}=\mathrm{CH}_{2} \frac{\text { Cold dil solution of }}{\text { Bayers reagent }} \mathrm{OH}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{OH}\,(\text {Glycol})$$$
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