JEE MAIN - Chemistry (2022 - 28th June Morning Shift - No. 17)
4.0 L of an ideal gas is allowed to expand isothermally into vacuum until the total volume is 2.0 L. The amount of heat absorbed in this expansion is ____________ L atm.
Answer
0
Explanation
Work done $=-P_{\text {ext }} \Delta \mathrm{v}$
$$ \because P_{\text {ext }}=0 \quad \text { (vacuum) } $$
$\therefore w=0, \quad\Delta U=0$ (as the process is isothermal)
So, $q=0$
$$ \because P_{\text {ext }}=0 \quad \text { (vacuum) } $$
$\therefore w=0, \quad\Delta U=0$ (as the process is isothermal)
So, $q=0$
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