JEE MAIN - Chemistry (2022 - 28th June Morning Shift - No. 13)
The formula of the purple colour formed in Laissaigne's test for sulphur using sodium nitroprusside is :
NaFe[Fe(CN)6]
Na[Cr(NH3)2(NCS)4]
Na2[Fe(CN)5(NO)]
Na4[Fe(CN)5(NOS)]
Explanation
$\left.\mathrm{S}^{2-}+\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NO}\right)\right]^{2-} \rightarrow\left[\mathrm{Fe}(\mathrm{CN})_{5}(\mathrm{NOS})\right]^{4-}$
Comments (0)
