JEE MAIN - Chemistry (2022 - 28th June Evening Shift - No. 2)
Consider the following statements :
(A) The principal quantum number 'n' is a positive integer with values of 'n' = 1, 2, 3, ...
(B) The azimuthal quantum number 'l' for a given 'n' (principal quantum number) can have values as 'l' = 0, 1, 2, ...... n
(C) Magnetic orbital quantum number 'ml' for a particular 'l' (azimuthal quantum number) has (2l + 1) values.
(D) $$\pm$$ 1/2 are the two possible orientations of electron spin.
(E) For l = 5, there will be a total of 9 orbital
Which of the above statements are correct?
Explanation
(A) Principle quantum number n is a positive integer and it's possible values are n = 1, 2, 3 ........
$$\therefore$$ A is correct.
(B) Azimuthal quantum number 'l' for a given 'n' can have values as l = 0, 1, 2 ....... (n $$-$$ 1)
$$\therefore$$ Statement B is wrong.
(C) Magnetic orbital quantum number ml for particular l has values from $$-$$ l to + 1 including zero means 2l + 1 values.
$$\therefore$$ Statement C is correct.
(D) $$ \pm \,\,{1 \over 2}$$ are the two possible orientation of electron spin.
$$\therefore$$ Statement D is correct.
(E) For l = 5, there will be a total of 11 orbitals.
$$l$$ = 0 $$\Rightarrow$$ 5 subshell
$$l$$ = 1 $$\Rightarrow$$ p subshell
$$l$$ = 2 $$\Rightarrow$$ d subshell
$$l$$ = 3 $$\Rightarrow$$ f subshell
$$l$$ = 4 $$\Rightarrow$$ g subshell
$$l$$ = 5 $$\Rightarrow$$ h subshell
We know,
Number of orbital in any subshell = 2$$l$$ + 1.
$$\therefore$$ For h subshell, number of orbitals = 2 $$\times$$ 5 + 1 = 11
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