JEE MAIN - Chemistry (2022 - 28th July Evening Shift - No. 16)
A gaseous mixture of two substances A and B, under a total pressure of $$0.8$$ atm is in equilibrium with an ideal liquid solution. The mole fraction of substance A is $$0.5$$ in the vapour phase and $$0.2$$ in the liquid phase. The vapour pressure of pure liquid $$\mathrm{A}$$ is __________ atm. (Nearest integer)
Answer
2
Explanation
Given that $X_{A}=0.2, Y_{A}=0.5, P_{T}=0.8 \mathrm{~atm}$
We know that $P_{A}=Y_{A} \times P_{T}$
$$ P_{A}=0.5 \times 0.8=0.4 $$
Now $P_{A}=X_{A} \times P_{A}^{\circ} \Rightarrow P_{A}^{\circ}=\frac{0.4}{0.2}=2 \mathrm{~atm}$
We know that $P_{A}=Y_{A} \times P_{T}$
$$ P_{A}=0.5 \times 0.8=0.4 $$
Now $P_{A}=X_{A} \times P_{A}^{\circ} \Rightarrow P_{A}^{\circ}=\frac{0.4}{0.2}=2 \mathrm{~atm}$
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