JEE MAIN - Chemistry (2022 - 28th July Evening Shift - No. 14)

2L of 0.2M H2SO4 is reacted with 2L of 0.1M NaOH solution, the molarity of the resulting product Na2SO4 in the solution is _________ millimolar. (Nearest integer)
Answer
25

Explanation

JEE Main 2022 (Online) 28th July Evening Shift Chemistry - Some Basic Concepts of Chemistry Question 80 English Explanation
Molarity of $\mathrm{Na}_2 \mathrm{SO}_4$ is $\frac{0.1}{4}=0.025 \,\mathrm{M}$

$=25 \,\mathrm{mM}$

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