JEE MAIN - Chemistry (2022 - 27th June Morning Shift - No. 5)

Which of the following will have maximum stabilization due to crystal field?
[Ti(H2O)6]3+
[Co(H2O)6]2+
[Co(CN)6]3$$-$$
[Cu(NH3)4]2+

Explanation

The given complexes are:

$\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+},\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+},\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{-3},\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}$

$\mathrm{CN}^{-}$is the strongest ligand among the given complexes CFSE value for the $\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{-3}$ complex will be highest as it has $d^{6}$ configuration with a CFSE value of $-2.40 \,\Delta_{0}+2 \mathrm{P}$, where $P$ represents pairing energy and $\Delta_{0}$ represents splitting energy in octahedral field.

The value of $\Delta_{0}$ is high for cyanide complexes.

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