JEE MAIN - Chemistry (2022 - 27th June Morning Shift - No. 17)
Acidified potassium permanganate solution oxidises oxalic acid. The spin-only magnetic moment of the manganese product formed from the above reaction is ____________ B.M. (Nearest integer)
Answer
6
Explanation
$\mathrm{KMnO}_{4}$ (acidic medium) $+\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \rightarrow \mathrm{CO}_{2}+\mathrm{Mn}^{+2}$
$\mathrm{Mn}^{+2}$ has 5 unpaired electrons
$\therefore $ Spin only magnetic moment $=\sqrt{5(5+2)}$
$$ \begin{aligned} &=\sqrt{5 \times 7} \\\\ &=\sqrt{35} \\\\ &\simeq 5.92 \text { B.M. } \\\\ &\simeq 6 \text { B.M. } \end{aligned} $$
$\mathrm{Mn}^{+2}$ has 5 unpaired electrons
$\therefore $ Spin only magnetic moment $=\sqrt{5(5+2)}$
$$ \begin{aligned} &=\sqrt{5 \times 7} \\\\ &=\sqrt{35} \\\\ &\simeq 5.92 \text { B.M. } \\\\ &\simeq 6 \text { B.M. } \end{aligned} $$
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