JEE MAIN - Chemistry (2022 - 27th June Evening Shift - No. 14)
Match List I with List II.
| List-I (Anion) |
List-II (gas evolved on reaction with dil.H$$_2$$SO$$_2$$) |
||
|---|---|---|---|
| (A) | CO$${_3^{2 - }}$$ | I. | Colourless gas which turns lead acetate paper black. |
| (B) | S$$^{2 - }$$ | II. | Colourless gas which turns acidified potassium dichromate solution green. |
| (C) | SO$${_3^{2 - }}$$ | III. | Brown fumes which turns acidified KI solution containing starch blue. |
| (D) | NO$${_2^ - }$$ | IV. | Colourless gas evolved with brisk effervescence, which turns lime water milky. |
Choose the correct answer from the options given below :
A-III, B-I, C-II, D-IV
A-II, B-I, C-IV, D-III
A-IV, B-I, C-III, D-II
A-IV, B-I, C-II, D-III
Explanation
$\mathrm{CO}_{3}^{2-}$ : On action of dil sulphuric acid, $\mathrm{CO}_{2}$ gas is released which turns lime water milky.
$\mathrm{S}^{2-} $ : On action of dil sulphuric acid, $\mathrm{H}_{2} \mathrm{~S}$ gas is released which turns lead acetate paper black.
$\mathrm{SO}_{3}^{2-}$ : On action of dil $\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{SO}_{2}$ gas is evolved which turns acidified potassium dichromate solution green.
$\mathrm{NO}_{2}^{-}$: On action of dil $\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{NO}_{2}$ gas is evolved which turns $\mathrm{KI}$ solution containg starch blue.
$\mathrm{S}^{2-} $ : On action of dil sulphuric acid, $\mathrm{H}_{2} \mathrm{~S}$ gas is released which turns lead acetate paper black.
$\mathrm{SO}_{3}^{2-}$ : On action of dil $\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{SO}_{2}$ gas is evolved which turns acidified potassium dichromate solution green.
$\mathrm{NO}_{2}^{-}$: On action of dil $\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{NO}_{2}$ gas is evolved which turns $\mathrm{KI}$ solution containg starch blue.
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