JEE MAIN - Chemistry (2022 - 27th June Evening Shift - No. 12)
Decarboxylation of all six possible forms of diaminobenzoic acids C6H3(NH2)2COOH yields three products A, B and C. Three acids give a product 'A', two acids gives a product 'B' and one acid give a product 'C'. The melting point of product 'C' is
63$$^\circ$$C
90$$^\circ$$C
104$$^\circ$$C
142$$^\circ$$C
Explanation
_27th_June_Evening_Shift_en_12_1.png)
Comments (0)
