JEE MAIN - Chemistry (2022 - 27th June Evening Shift - No. 11)
Match List-I with List-II.
| List-I | List-II | ||
|---|---|---|---|
| (A) | _27th_June_Evening_Shift_en_11_1.png) |
I. | $$B{r_2}$$ in $$C{S_2}$$ |
| (B) | _27th_June_Evening_Shift_en_11_2.png) |
II. | $$N{a_2}C{r_2}{O_7}/{H_2}S{O_4}$$ |
| (C) | _27th_June_Evening_Shift_en_11_3.png) |
III. | $$Zn$$ |
| (D) | _27th_June_Evening_Shift_en_11_4.png) |
IV. | $$CHC{l_3}/NaOH$$ |
Choose the correct answer from the options given below :
A-IV, B-III, C-II, D-I
A-IV, B-III, C-I, D-II
A-II, B-III, C-I, D-IV
A-IV, B-II, C-III, D-I
Explanation
_27th_June_Evening_Shift_en_11_5.png)
_27th_June_Evening_Shift_en_11_6.png)
_27th_June_Evening_Shift_en_11_7.png)
$\therefore$ Correct match is (A) - IV, (B) - III, (C) - II, (D) - I
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