JEE MAIN - Chemistry (2022 - 27th July Morning Shift - No. 22)
Optical activity of an enantiomeric mixture is $$+12.6^{\circ}$$ and the specific rotation of $$(+)$$ isomer is $$+30^{\circ}$$. The optical purity is __________$$\%$$.
Answer
42
Explanation
Optical purity $=\frac{\text { Total rotation }}{\text { Specific rotation }} \times 100$
$$ \begin{aligned} &=\frac{12 \cdot 6}{30} \times 100 \\\\ &=42 \% \end{aligned} $$
$$ \begin{aligned} &=\frac{12 \cdot 6}{30} \times 100 \\\\ &=42 \% \end{aligned} $$
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