JEE MAIN - Chemistry (2022 - 27th July Evening Shift - No. 2)
Match List - I with List - II.
| List - I | List - II | ||
|---|---|---|---|
| (A) | $$\psi_{\mathrm{MO}}=\psi_{\mathrm{A}}-\psi_{\mathrm{B}}$$ | (I) | Dipole moment |
| (B) | $$\mu=Q \times r$$ | (II) | Bonding molecular orbital |
| (C) | $$\frac{\mathrm{N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}}{2}$$ | (III) | Anti-bonding molecular orbital |
| (D) | $$\psi_{\mathrm{MO}}=\psi_{\mathrm{A}}+\psi_{\mathrm{B}}$$ | (IV) | Bond order |
Choose the correct answer from the options given below :
$$(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{III})$$
$$(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{II})$$
$$(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})$$
$$(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{I})$$
Explanation
$\Psi_{A}-\Psi_{B}=\Psi_{M O}$ is anti-boding molecular orbital
$$ \begin{aligned} &\mu=Q \times r \text { is dipole moment } \\\\ &\frac{N_{b}-N_{a}}{2}=\text { bond order } \\\\ &\Psi_{\mathrm{A}}+\Psi_{\mathrm{B}}=\Psi_{\mathrm{MO}} \text { is boding molecular orbital. } \end{aligned} $$
$$ \begin{aligned} &\mu=Q \times r \text { is dipole moment } \\\\ &\frac{N_{b}-N_{a}}{2}=\text { bond order } \\\\ &\Psi_{\mathrm{A}}+\Psi_{\mathrm{B}}=\Psi_{\mathrm{MO}} \text { is boding molecular orbital. } \end{aligned} $$
Comments (0)
