JEE MAIN - Chemistry (2022 - 27th July Evening Shift - No. 14)
$$\mathrm{Fe}^{3+}$$ cation gives a prussian blue precipitate on addition of potassium ferrocyanide solution due to the formation of :
$$\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]_{2}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]$$
$$\mathrm{Fe}_{2}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{2}$$
$$\mathrm{Fe}_{3}\left[\mathrm{Fe}(\mathrm{OH})_{2}(\mathrm{CN})_{4}\right]_{2}$$
$$\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}$$
Explanation
$4 \mathrm{Fe}^{3+}+3\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{-4} \longrightarrow\underset{\text{Prussian Blue}} {\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3}$
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