JEE MAIN - Chemistry (2022 - 27th July Evening Shift - No. 10)
Match List - I with List - II.
| List - I | List - II | ||
|---|---|---|---|
| (A) | _27th_July_Evening_Shift_en_10_1.png) |
(I) | Gatterman Koch reaction |
| (B) | $$C{H_3} - CN\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{{H_3}{O^ + }}^{SnC{l_2}/HCl}} C{H_3} - CHO$$ |
(II) | Etard reaction |
| (C) | _27th_July_Evening_Shift_en_10_2.png) |
(III) | Stephen reaction |
| (D) | _27th_July_Evening_Shift_en_10_3.png) |
(IV) | Rosenmund reaction |
Choose the correct answer from the options given below :
$$(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{I})$$
$$(\mathrm{A})-(\mathrm{I}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{IV})$$
$$(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{I})$$
$$(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})$$
Explanation
_27th_July_Evening_Shift_en_10_4.png)
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