JEE MAIN - Chemistry (2022 - 26th June Morning Shift - No. 2)
If the radius of the 3rd Bohr's orbit of hydrogen atom is r3 and the radius of 4th Bohr's orbit is r4. Then :
$${r_4} = {9 \over {16}}{r_3}$$
$${r_4} = {16 \over {9}}{r_3}$$
$${r_4} = {3 \over {4}}{r_3}$$
$${r_4} = {4 \over {3}}{r_3}$$
Explanation
We know,
$$r = {r_0} \times {{{n^2}} \over z}$$
For hydrogen atom,
$$\therefore$$ $${r_3} = {r_0} \times {{{3^2}} \over 1}$$
$$ \Rightarrow {r_0} \times {{{r_3}} \over 9}$$
and $${r_4} = {r_0} \times {{{4^2}} \over 1}$$
$$ = {{{r_3}} \over 9} \times 16$$
$$ = {{16} \over 9}{r_3}$$
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